Question

A car travels first 30 km with a uniform speed of 60 km/h and then next 30 km with a uniform speed of 30 km/h. Find average speed of the car during the journey.
pls answer Asap

Answer 1

Answer:

Answer:

V1 = 60km/hr D1 = 30 km

T1 = ?

V2 = 40 km/hr D2 = 30 km

T2 = ?

Total Time = T1+T2

We know that,

velocity = Distance /Time

Therefore, V1 = D1/T1 or T1 = D1/ V1 =>

T1 = 30 km / 60 km /hr = 1/2 hr = V2 = D2/T2 or T2 = D2/ V2 =

=> T2 = 30 km / Hence, /hr 3/4 hr Total Time = T1 + T2 = 1/2 +

40 km

=

3/4 = 5/4 hrs

we know that,

Average Velocity = Total Distance / total time taken = 30 30 / 5/4

= 60/5/4 = =

48 km /hr

Hence Average Velocity is 48km/ hr

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Answer 2

Answer:-

40km/hr

Explanation:-

Given :

A car travels first 30km with a uniform speed of 60km/hr and then next 30km with a uniform speed of 30km/hr.

To Find :

Average Speed = ?

Solution :

$\sf{}We\ know,Average\ Speed=\dfrac{Total\ distance\ travelled}{Total\ Time\ Taken}$

So, let’s find it’s total distance and total time

Total distance,

=> (30 + 30)km

=> 60km

$\sf{}We\ know\ Speed =\dfrac{Distance}{Time}$

$\sf{}So,Time=\dfrac{Diatance}{Speed}$

$\sf{}Time\ taken\ for\ first\ 30km:$

$\sf{}\implies T_1=\dfrac{d_1}{v_1}\\\\\\\sf{}\implies T_1=\dfrac{30}{60}\\\\\\\sf{}\implies T_1=\dfrac{3}{2}\\\\\\\sf{}\implies T_1=0.5hr$

$\sf{}Time\ taken\ for\ next\ 30km:$

$\sf{}\implies T_2=\dfrac{d_2}{v_2}\\\\\\\sf{}\implies T_1=\dfrac{30}{30}\\\\\\\sf{}\implies T_1=1hr$

$\sf{}Total\ time\ taken=(0.5+1)hr$

$\sf{}\implies 1.5$

$\sf{}Average\ speed =\dfrac{60}{1.5}$

$\sf{}\implies 60\div {1.5}$

$\sf{}\implies 60\div \dfrac{15}{10}$

$\sf{}\implies 4\times 10$

$\sf{}\therefore 40 km/hr$

Hence,Average Speed is 40km/hr.