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2)Fe304
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Rust is apparently a hydrated form of iron(III)oxide. The formula is approximately Fe2O3•32H2O, although the exact amount of water is variable. (Note that this is about halfway between iron(III) hydroxide, Fe(OH)3 or ½{Fe2O3•3H2O], and anhydrous Fe2O3)
so Fe2O3 is the answer
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