a car travels from stop A to stop B with the speed of 30 km per hour and then returns back to A with a speed of 50 km per hour.find the displacement of the car,distance travelled by the car, average speed of the car .
aashu004:
what is the time taken???
we cannot find out the time taken with the help of given information it must be given in the question itself.
time taken will be 2 hr
Prashant i had wriiten the correct question
can u explain how the time taken is 2hours
Answers
Answered by
4
Displacement is defined as the minimum distance between initial and final positions
As the car came back to it's initial position So, displacement = 0m
Distance = S1t1+S2t2
So, we require time period of the journey to find out the distance.
Avg speed =(total distance covered/total time taken)
=2d/((d/30)+(d/50))
=(2dx150)/(5d+3d)
=300d/8d
=37.5km/hr
As the car came back to it's initial position So, displacement = 0m
Distance = S1t1+S2t2
So, we require time period of the journey to find out the distance.
Avg speed =(total distance covered/total time taken)
=2d/((d/30)+(d/50))
=(2dx150)/(5d+3d)
=300d/8d
=37.5km/hr
its wrong answers
what is the right one?
distance will be 80km
average speed will be 40km/hr
sorry dear i was wrong ....your answer is correct
Answered by
1
Answer:
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Explanation:
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