Calculate the no.of moles and molecules in 19.86gm of Pb(NO3)2
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Hello friend
Your answer is given below :
___________________________
Given that,
Weight of Pb( NO3)2 => 19.86 gm
Molecular weight. => 331 u
We know that,
No. Of moles = given weight / mole.Weight
=> 19.86 / 331
=> 0.06
And
No. Of molecules=avagadro no. X no. Of moles
=> 6.023 x 10 ^23 x 0.06
=> 0.36138 × 10^23
=> 3.6138 × 10^22
So,
The no. of moles = 0.06
And no. of molecules = 3.6138× 10^22
_________________________________
Have a nice day friend
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Your answer is given below :
___________________________
Given that,
Weight of Pb( NO3)2 => 19.86 gm
Molecular weight. => 331 u
We know that,
No. Of moles = given weight / mole.Weight
=> 19.86 / 331
=> 0.06
And
No. Of molecules=avagadro no. X no. Of moles
=> 6.023 x 10 ^23 x 0.06
=> 0.36138 × 10^23
=> 3.6138 × 10^22
So,
The no. of moles = 0.06
And no. of molecules = 3.6138× 10^22
_________________________________
Have a nice day friend
✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️
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