A car uniformily accelrates from 18km/hr to 36 km/hr in 5 sec calculate the accelration and distance covered by car in that time??
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here......
initial velocity=18kmph=5m/s.
final velocity=10m/s.
we know v=u+at.
so 10=5+5a
a=1m/s^2.
we have
distance=ut +1/2at^2
so
distance=5+1/2(1)(5^2)
=5+12.5=17.5m
initial velocity=18kmph=5m/s.
final velocity=10m/s.
we know v=u+at.
so 10=5+5a
a=1m/s^2.
we have
distance=ut +1/2at^2
so
distance=5+1/2(1)(5^2)
=5+12.5=17.5m
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