The side of a triangle are 40 cm ,30 cm ,5.0 cm find the length of the altitude corresponding of the side 50 cm
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Let a = 40cm, b= 30cm and c = 50 cm.
Area of a triangle = √s (s-a) (s-b) (s-c)
Where s = (a+b+c)/2
= (40+30+50)cm / 2
= 120cm/2
= 60cm
Area = √60 (60-40) (60-30) (60-50) cm²
= √60 × 20 × 30 × 10
= √360000
= 60 cm²
Let the altitude drawn corresponding of the side 50cm be h.
Base = 50cm
Area = 60cm²
Area of a triangle = 1/2 × base × height
=> 60cm² = 1/2 × 50cm ×h
=> h = 60cm² × 2 / 50cm
=> h = 2.4 cm
Ans. = The length of the altitude is 2.4cm.
Hope it helps!! ^^
Area of a triangle = √s (s-a) (s-b) (s-c)
Where s = (a+b+c)/2
= (40+30+50)cm / 2
= 120cm/2
= 60cm
Area = √60 (60-40) (60-30) (60-50) cm²
= √60 × 20 × 30 × 10
= √360000
= 60 cm²
Let the altitude drawn corresponding of the side 50cm be h.
Base = 50cm
Area = 60cm²
Area of a triangle = 1/2 × base × height
=> 60cm² = 1/2 × 50cm ×h
=> h = 60cm² × 2 / 50cm
=> h = 2.4 cm
Ans. = The length of the altitude is 2.4cm.
Hope it helps!! ^^
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