each side of a rhombus is 6 cm long .its area is 10.2 square cm.find height of the rhombus
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we know that, area of rhombus =as
so,
ATQ
area is 10.2 cm Sq.
side is 6cm
so,
let altitude be x
10.2 = 6 × x
( when any decimal removes it divided by no. of zeros which are given after decimal )
102÷10 =6× x
51 ÷5 =6 × x
1.2 = 6 × x
12 ÷ 10 = 6 × x
12 ÷ 10 × 6 = x
(in cutting we get 5 )
so , x = 5
##.. hope it helpful ##..
so,
ATQ
area is 10.2 cm Sq.
side is 6cm
so,
let altitude be x
10.2 = 6 × x
( when any decimal removes it divided by no. of zeros which are given after decimal )
102÷10 =6× x
51 ÷5 =6 × x
1.2 = 6 × x
12 ÷ 10 = 6 × x
12 ÷ 10 × 6 = x
(in cutting we get 5 )
so , x = 5
##.. hope it helpful ##..
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