Math, asked by santa19, 9 hours ago

A card is drawn at random from a well shuffled pack of 52 cards. Find the probability of drawing (i) a club, (ii) a king or an ace, (iii) not a spade​

Answers

Answered by harshchhawal233
3

Answer:

There are 4 suits in a pack of 52 cards

13− Heart

13− Diamond

13− Spades

13− clube

Each suit has 1 ace, 1 jack, 1 king, 1 queen

Face cards =king, queen, jack

Total face card =12

Red cards (Heart+Diamond) =26

Black cards (Spades+Club) =26

Total king cards =4

Total no. of cards(neither a king nor a red card) = Total black cards − 2 Black kings =26−2=24

P(probability of drawing card which is neither a king nor a red card)=

52

24

Answered by Op06
4

Answer:

(i) 1/4

(ii) 2/13

(iii) 3/4

Step-by-step explanation:

(i)There are 13 clubs therefore,

P(a club): 13/52

             = 1/4

(ii)There are 4 kings and 4 aces therefore,

P(king or ace): 8/52

                     = 2/13

(iii)There are 39 cards that are not a spade

P(not a spade): 39/52

                       = 3/4

Attachments:
Similar questions