Question

A cell of emf 2volt and internal resistance 4 is connected to a 12 ohm external resistance what will be rhe potential difference across the terminal of cell

Answer 1

current i=E/(R+r)

i=2/(12+4)

i=2/16

i=0.125A

V=E-ir

V=2-(0.125×4)

V=2-0.5

V=1.5volts

hope the answer is helpful.