Question

If the zero of polynomial x^2-px+q are 3and2 find the value of p and q

Answer 1

$\mathfrak{Answer:-}$

x²-px+q

Substuting 3 in the above eq.

3²-3p+q = 0 {Since 3 is a zero of the polynomial}

9-3p+q=0

-3p+q = -9--------------------eq.1

Now substituting 2 in the eq. we get

2²-2p +q = 0

-2p + q = -4 -------------eq.2

Eq.1 - eq.2

-3p+q = -9

2p - q = 4

-p = -5

p = 5

q = 6

Hence,

$\boxed{p=5,q=6}$