a centigrade and a fahrenheit thermometer are dipped in boiling water . The water temperature is lowered until the fahrenheit thermometer registers 140. What is the fall in temperature as registered bu centigrade thermometer
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(C-LFP)÷(UFP-LFP) = (F-32)÷180
C is temp. in celcius scale
(C-0°)÷(100°-0°) = (140-32)÷180
on solving..
C=6°
(C-LFP)÷(UFP-LFP) = (F-32)÷180
C is temp. in celcius scale
(C-0°)÷(100°-0°) = (140-32)÷180
on solving..
C=6°
gummaliki1927:
answer is 60C BUT THANKS FOR THE PROCEDURE
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Explanation:
The water temperature is lowerd until the Fahrenheit thermometer registenrs 140∘. What is the fall in temperature as registered by the centigrade thermometer? ∴ Fall temperature =40∘C.
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