A certain force acts on a body of masses 10kg and changes its velocity to 2m\s to 5m\s. Calculate work done by force
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Answered by
1
mass=10 kg , u =2m/s , v =5m/s
we know ,,work done =1/2 ×m (v×2 - u×2)
1/2×10(4-25)
5×(-21)
-105J
we know ,,work done =1/2 ×m (v×2 - u×2)
1/2×10(4-25)
5×(-21)
-105J
Answered by
0
Mass= 10 kg
initial velocity(u)=2m/s
final velocity(v)=5m/s
work done = 1/2 x m x (v^2-u^2)
=1/2 x 10 x-21
= -105 J
initial velocity(u)=2m/s
final velocity(v)=5m/s
work done = 1/2 x m x (v^2-u^2)
=1/2 x 10 x-21
= -105 J
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