If the angle of elevation of the sun changes from 45 degree to 60degree ,then the length of the shadow of a pillar decreases by 10m .the height of the pillars is
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In∆ABC, tan 60°=P/B
√3=AB/x
√3x=AB - (i)
In ∆ABD, tan 45°= P/B
1 = AB/10
10m=AB
Therefore,. The height of the pillar is 10m.
√3=AB/x
√3x=AB - (i)
In ∆ABD, tan 45°= P/B
1 = AB/10
10m=AB
Therefore,. The height of the pillar is 10m.
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