a certain force exerted for 1.2 second raises the speed of an object from 108m/s to4.2 m/s. what the same force is applied for 2second . how much does the velocity change in 2 seconds
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subhendukumar:
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f -?
t-1.2s
u-108m/s
v-4.2m/s
f-ma
f-m(v-u)/t
f=-86.5 m N
t=2
f=ma
-86.5m=ma
a=-86.5
a=v-u/t
-86.5=/(v-u)÷2
-173m/s=change in velocity
t-1.2s
u-108m/s
v-4.2m/s
f-ma
f-m(v-u)/t
f=-86.5 m N
t=2
f=ma
-86.5m=ma
a=-86.5
a=v-u/t
-86.5=/(v-u)÷2
-173m/s=change in velocity
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