Physics, asked by salman2699, 1 year ago

A certain force exerted for 1.2s raises the speed of an object from 1.8m/s to 4.2m/s . Find its acceleration if mass of the object is5.5kg . Calculate the force applied.

Answers

Answered by skh2
6
Time = 1.2 second
Initial velocity = 1.8m/sec
Final velocity = 4.2m/sec

Now,
Acceleration = final v - initial v/time
So,
a =  \frac{4.2 - 1.8}{1.2}  =  \frac{2.4}{1.2}  = 2
So,
Acceleration = 2m/sec²

Mass (given) = 5.5 kg
Now,
force = mass \times acceleration
So,
F= 5.5 * 2 = 11N

Hope this will be helping you

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Sahil khirwal
Answered by RYTHUM
0

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