Question

a certain loud speaker emits 30W of sound power. A small mic of effective cross-sectional area...

Answer 1

Answer:-

Question is incomplete. cross section area = 0.75 sq. cm.

Find sound intensity of microphone & what power it received ?

Sound Intensity = P / A = 30 / 0.75 x 10 ^ (-4) = 4 x 10^5 W/m²

Assuming both are at same location, then power received will also be same. Power = 30 W.