A certain sum of money of money at compound interest becomes rupees 7396 in two years and rupees 7950.70 in three years. find the rate of interest
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We know that A = P(1+r/100)
7396 = P(1+r/100)^2 ---------------- (1)
7950.70 = P(1+r/100)^3 ----------------- (2)
On solving (2) by (1), we get
7950.70/7396 = P(1+r/100)^3/P(1+r/100)^2
1.075 = 1 + r/100
r/100 = 0.075
r = 7.5%.
Hope this helps!
7396 = P(1+r/100)^2 ---------------- (1)
7950.70 = P(1+r/100)^3 ----------------- (2)
On solving (2) by (1), we get
7950.70/7396 = P(1+r/100)^3/P(1+r/100)^2
1.075 = 1 + r/100
r/100 = 0.075
r = 7.5%.
Hope this helps!
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