Question

A charge 3 Coulomb experiences a force 300 N when placed in a uniform electric field. The potential difference between two points separated by a distance of 10 cm along the field line is:
1. 10 V
2. 90 V
3. 1000 V
4. 9000 V

Answer 1

10 volt is the answer as E=force/q,then E is also equal to =dv/dr ,where dr is distance and dv is potential difference

Answer 2

Answer:

10 Volts

Explanation:

Force = F = 3000 N  (Given)

Charge = q = 3 coulomb  (Given)

Distance = d = 10 cm  (Given)

According to the formula -

F = qE

F = qV/D

Where, F is the force , q is the charge, V is the potential difference  and d is the distance between two points

3000 = 3 × V/10×10-²

V = 1000

Thus, the potential difference between two points separated by a distance of 10 cm along the field line is 1000 Volts.