Question

a charge q is dropped from a height h and a horizontal magnetic field of magnitude B is acting.if m is the mass of the charge then it's velocity is ?​

Answer 1

Answer:

Explanation:ANSWER

Given:

B

=B  

0

​  

 

j

^

​  

 

E

=E  

0

​  

 

k

^

 

The particle have initial velocity zero, So electric field will be responsible for to move in opposite direction of electric field.

Magnetic force on the particle does not increase the speed of the particle since  

F

 

mag

​  

.  

v

=0   (∠90  

∘

)

F

 

electric

​  

=qE  

k

^

 

⇒  

a

=  

m

qE

​  

 

k

^

 

Since acceleration is constant applying the one-dimensional kinematics equation:

v  

2

−u  

2

=2a  

z

​  

 

∴v  

2

=  

m

2qEz

​  

 since initial speed u=0

⇒v=  

m

2qEz

​  

 

​