Question

A charged particle having charge q accelerated through a potential difference v enters a perpendicular magnetic field in which it experiences a force f. If v increased to 5v the particle experiences a force

Answer 1

Answer:

5F

Explanation:

F = q (v×B)

here, q and B are constants.

F1= q (v1×B)

F2= q(v2×B)

V1 is V and V2 is 5v

where vbis original velocity and V2 is increased velocity and F1=initial force and F2 is final force

F1 = q (v×B)

F2 = q(5v×B)

hence F1=5F2

F2= (F1)/5

therefore, the particle experience force of 5F.

Answer 2

Answer:

not a correct answer ita answer is root 5F