Question

A child drops a ball from a height of 10m assume that it's velocity increase uniformly at the rate 16m square? Find the velocity with which ball should watch around. (2)The time taken by the ball to reach the ground

Answer 1

Explanation:

1.) distance = 10m

acceleration = 16m/s2

initial velocity = 0m/s

final velocity =>

v2 = u2+2as

v2 = 02+2*16*10

v2 = 0+ 320

v = 17.88 m/s

2.) Time

v = u+at

17.88 = 0+16t

17.88= 16t

t = 17.88/16 s

t = 4.47/4 s