Question

A child went 90 m in the east to look for his father, then he turned right and went 20 m. after this he turned right and after going 30 m he reached to his uncle's house. his father was not there. from there he went 100 m to his north and met his father. how far did he meet his father from the starting point?

Answer 1

Hey, sup!

The child went 90 m in the East.

Then he turned right and went 20 m.(that means 20m South)

After this he turned right and after going 30 m he reached to his uncle's house.(that means 30 West)

From there he went 100 m to North.

It makes a right angle triangle and we can solve it using Pythagoras theorem.
Here perpendicular and base is given and hypotenuse is to be calculated.

Base= 90m-30m=60m.
Perpendicular=100m-20m= 80m.
Hypotenuse= √60^2+80^2.
=√3600+6400.
=√10000m^2.
= 100m.

So, The child met his father 100m far from the starting point.

Hope you understand and it helps.

Answer 2

Answer:

Step-by-step explanation:

Clearly, the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 meters upto C, then turns right and moves 30 metre upto D. Finally he moves towards North for 100 metres upto E where he meets his father.

So AB=90 metre, BF=CD= 30 metre,

So, AF=AB−BF= 60 metres

Also DE=100 metres

DF=BC= 20 metres

So, EF=DE−DF= 100−20 = 80 metres

In right angled △ AFE

AE =

AF

2

+EF

2

​

=

60

2

+80

2

​

=100 meters

So from starting point his father was 100 metre away.

option B