Math, asked by nirajgupta, 1 year ago

a chord of a circle of radius 10 centimetre substance a right angle at its Centre the length of Chord is

Answers

Answered by Dsnyder
0
I think the complete question is this:-
A chord of circle 10cm subtends a right angle at the centre. Find the area of the corresponding : minor segmemt and major segment..

Here is the answer:-

Radius of the circle = 10 cm

Major segment is making 360° - 90° = 270°

Area of the sector making angle 270° 

                                 = (270°/360°) × π r2 cm2

                                           = (3/4) × 102π  = 75 π cm2 
                                = 75 × 3.14 cm2 = 235.5 cm2 
∴ Area of the major segment = 235.5 cm2

Height of ΔAOB = OA = 10 cm

Base of ΔAOB = OB = 10 cm

Area of ΔAOB = 1/2 × OA × OB

                         = 1/2 ×10 × 10 = 50 cm2

Major segment is making  90°

 Area of the sector making angle 90°        

= (90°/360°) × π r2 cm2

                                          = (1/4) × 102π  = 25 π cm2 
                               = 25 × 3.14 cm2 = 78.5 cm2 
Area of the minor segment = Area of the sector making angle 90° - Area of ΔAOB

                                            = 78.5 cm2 -  50 cm2 = 28.5 cm2



Answered by aditya155ku
2
when we find length of chord we use .thita/360 2Πr formula put the value of thita =90 and put r= 10 cm and easily find amswer
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