A circle and rectangle have the same perimeter.The sides of the rectangle are 18cm and 26cm. What will be the area of the circle in m
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The perimeter of circle = 2πR
The perimeter of rectangle = 2(L + B)
Where R is the radius if the circle, L is the length of the rectangle and B is the breadth of the rectangle.
As given above,
2πR = 2(L + B)
πR = (18 + 26)
πR = 44
R = 44/π I'm
Now, Area of the circle = π R^2
Substituting the value of R in above equation and we get,
Area = π (44/π)^2
= (44)(44/π)
= 1936/π
Now π = 22/7
Thus,
Area = (1936)(7/22)
Area = 616 cm^2
The perimeter of rectangle = 2(L + B)
Where R is the radius if the circle, L is the length of the rectangle and B is the breadth of the rectangle.
As given above,
2πR = 2(L + B)
πR = (18 + 26)
πR = 44
R = 44/π I'm
Now, Area of the circle = π R^2
Substituting the value of R in above equation and we get,
Area = π (44/π)^2
= (44)(44/π)
= 1936/π
Now π = 22/7
Thus,
Area = (1936)(7/22)
Area = 616 cm^2
Answered by
2
Perimeter of circle ( Circumference) = 2pi r
PERIMETER of rectangle = 2 ( L + B)
ATQ, PERIMETER OF CIRCLE = PERIMETER OF RECTANGLE
2 * 22 /7 *r = 2 ( 26 + 18 )
22 /7 * r = 44
r = 44 × 7 / 22
r = 14 cm.
Area of circle, = pi r ^2
=> 22/7 × 14 × 14
= 22 * 28
=> 616 cm ^2.
PERIMETER of rectangle = 2 ( L + B)
ATQ, PERIMETER OF CIRCLE = PERIMETER OF RECTANGLE
2 * 22 /7 *r = 2 ( 26 + 18 )
22 /7 * r = 44
r = 44 × 7 / 22
r = 14 cm.
Area of circle, = pi r ^2
=> 22/7 × 14 × 14
= 22 * 28
=> 616 cm ^2.
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