Question

a circle touches all the four sides of a quadrilateral ABCD whose sides are AB et 6 cm, BC = 9
cm and CD = 8 cm. Find the length of side AD.

Answer 1

Answer:

following is answer

Step-by-step explanation:

Let the circle touches the sides AB, BC, CD and DA of the quadrilateral ABCD at points P, Q, R and S respectively.

Since the lengths of the tangents drawn from an external point are equal. So

DR = DS (tangents on circle from point D)

CR = CQ (tangents on circle from point C)

BP = BQ (tangents on circle from point B)

AP = AS (tangents on circle from point A)

Adding all these equations

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

CD + AB = AD + BC

AD = 8 cm + 6 cm - 9 cm = 5 cm

Answer 2

Step-by-step explanation:

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