Question

A circle with centre (3,2) passes through the points (6,3) what is the radius of the circle​

Answer 1

Answer:

Step-by-step explanation:

A circle passes through point P≡(6,3) having center as B≡(3,2)

this implies segment BP is the radius of the circle

Radius of the circle = d (B,P) =$\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }$

                                              = $\sqrt{(6-3)^{2} +(3-2)^2} = \sqrt{3^2 + 1^2}$

                                             =$\sqrt{9 +1} = \sqrt{10} units$