A circular flower bed is surrounded by a path 4m wide.the diameter of the flower bed is 66 m .what is the area of path(π=3.14)
Answers
Answer:
427.04m^2
Step-by-step explanation:
3.14 * 33 * 33
= 3419.46
3.14 × 35 ×35
=3846.5
3846.5 -3419.46
=427.04
Given:-
Width of the path = 4 m
Diameter of the flower bed = 66 m
To find:-
The area of the path.
Solution:-
Diameter of the flower bed is 66 m.
So, Radius of the flower bed =diameter/2
= (66/2)m
= 33m.
Now, Area of flower bed = π r²
⟹ Area = 3.14 × (33)²
⟹Area = 3.14 × 1089.
⟹Area = 3419.49 m²
Now, Diameter of large circle
= Width of path + diameter of flower bed.
= ( 66 + 4)m
= 70m
So, Radius of large circle
= (diameter/ 2)
= (70/2)m
= 35 m.
Now, Area of large circle = π r²
➟Area = 3.14 × (35)²
➟Area = 3.14 × 1225.
➟Area = 3846.5
So, now Area of path
= Area of large circle - Area of flower bed
= 3846.5 - 3419.49
= 427.01 m² (ans)
Therefore, the area of the path is 427.01 m².
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