Question

A circular frame of area 15 sq.m. is placed in a uniform electric field of 30N/C with the plane of the frame making an angle of 30° with the direction of field. What is the electric flux through the frame?

Answer 1

Given:

Area of circular frame $A = 15 m^{2}$

Electric field $E = 30 \frac{N}{C}$

The angle between plane of the frame and electric field is 30°

To Find: Electric flux,

From the formula of electric flux,

   $\phi = E.A$

   $\phi = EA \cos \theta$

Where $\theta =$ angle between surface normal and electric field,

Here $\theta =$ 90° - 30° = 60°

   $\phi = EA\cos 60$

   $\phi = 30 \times 15 \cos 60$

   $\phi = 225$ $Vm$

Therefore, the electric flux through the frame is 225 Vm