a circular loop has a radius of 5 centimetre and it is carrying a current of 0.1 ampere its magnetic moment is
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nn is the number of loops
ii is the current throught the coil
AA is the area of cross section of the coil
n̂ is the unit vector along the direction of the magnetic moment
Since there is only one loop, n=1n=1
Therefore,
μ→=0.1×π(0.1)2μ→=0.1×π(0.1)2 n̂
=10−3π=10−3π n̂
And to find n̂, imagine the coil in front of you such that the current in the coil is flowing in counter-clockwise direction (as seen by you)
Now curl your fingers along the circumference of the loop, you thumb will point in the direction of n̂ which is also the direction of the magnetic moment of the loop
ii is the current throught the coil
AA is the area of cross section of the coil
n̂ is the unit vector along the direction of the magnetic moment
Since there is only one loop, n=1n=1
Therefore,
μ→=0.1×π(0.1)2μ→=0.1×π(0.1)2 n̂
=10−3π=10−3π n̂
And to find n̂, imagine the coil in front of you such that the current in the coil is flowing in counter-clockwise direction (as seen by you)
Now curl your fingers along the circumference of the loop, you thumb will point in the direction of n̂ which is also the direction of the magnetic moment of the loop
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