a circular park of radius 25m has a road 5m wide running around it find the cost of metalling the road at the rate of 18.20
Answers
Answered by
1
Area of road is (pi (30)^2 - pi (25)^2)
= 275 pi sq m
Coast of 1sq m = 18.20
Cost of 275 pi sq m = 18.20*275*3.14
=15,715.7
= 275 pi sq m
Coast of 1sq m = 18.20
Cost of 275 pi sq m = 18.20*275*3.14
=15,715.7
rohit478:
galat hain answer oooooooo
Answered by
1
there is circle of radius 25m in which there is road of 5m wide
radius of park without road = 25-5 = 20m
area of road = area of park with road - area of park without road
=pie(R^2 - r^2)
=22/7(25^2-20^2)
=22/7(50-40)
=22/7(10)
=220/7
cost of metaling 1 m sq= 18.20ruppes
cost of metaling 220/7 m sq= 18.20*220/7= 572
therefore cost of metaling road = 572 Ruppes
radius of park without road = 25-5 = 20m
area of road = area of park with road - area of park without road
=pie(R^2 - r^2)
=22/7(25^2-20^2)
=22/7(50-40)
=22/7(10)
=220/7
cost of metaling 1 m sq= 18.20ruppes
cost of metaling 220/7 m sq= 18.20*220/7= 572
therefore cost of metaling road = 572 Ruppes
galat hain hahahahaha
Similar questions