a solid cube of side 12cm is cut into eight cubes of equal volume.what will be the side of the new cube?also ,find the ratio between their csa ? please help 9 class question
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Side (a) of cube = 12 cm
Volume of cube = (a)3 = (12 cm)3 = 1728 cm3
Let the side of the smaller cube be a1.
Volume of 1 smaller cube
⇒ a1 = 6 cm
Therefore, the side of the smaller cubes will be 6 cm.
Ratio between surface areas of cubes
Therefore, the ratio between the surface areas of these cubes is 4:1.
Volume of cube = (a)3 = (12 cm)3 = 1728 cm3
Let the side of the smaller cube be a1.
Volume of 1 smaller cube
⇒ a1 = 6 cm
Therefore, the side of the smaller cubes will be 6 cm.
Ratio between surface areas of cubes
Therefore, the ratio between the surface areas of these cubes is 4:1.
Anonymous:
you helped me
Answered by
1
side of cube=12cm
volume=side^3
=12×12×12
=1728cm^3
if it's divided into 8 smaller cubes then the volume of the small cubes will be=1728/8
=216cm^3
therefore side of the smaller cube=side^3
side^3=216
side=6cm
CSA of big cube=6a^2
=6×12^2
=6×144
=864cm^2
CSA of smaller cube=6a^2
=6×6^2
=6×36
=216cm^2
ratio:-
864:216
4:1
hope this helps...
volume=side^3
=12×12×12
=1728cm^3
if it's divided into 8 smaller cubes then the volume of the small cubes will be=1728/8
=216cm^3
therefore side of the smaller cube=side^3
side^3=216
side=6cm
CSA of big cube=6a^2
=6×12^2
=6×144
=864cm^2
CSA of smaller cube=6a^2
=6×6^2
=6×36
=216cm^2
ratio:-
864:216
4:1
hope this helps...
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