Question

A circular rug has a circular table at the middle. The diameter of the rug is 6 meters while the diameter of the table is 2 meters. What area of the rug is left after putting the table over the middle of the rug?​

Answer 1

Given,

Diameter of rug = 6 metres

Diameter of table = 2 metres

To find,

The area left after putting the table over the middle of the rug.

Solution,

We can easily solve this mathematical problem by using the following mathematical process.

Radius of rug = (6/2) = 3 metres

Radius of table = (2/2) = 1 metre

Area of rug (A1) = π × (3)² = 28.27 m²

Area of table (A2) = π × (1)² = 3.14 m²

Remaining area = (A1-A2) = (28.27-3.14) = 25.13 m²

Hence, 25.13 m² will be left.

Answer 2

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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Answer 3

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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Answer 4

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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Answer 5

Step-by-step explanation:

Given:-

A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.

To find:-

Time taken to become velocity 80 m/s.

Equation Used:-

{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}

FirstEquationofMotion:v=u+at

Here,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time taken

Solution:-

Using first equation of motion,

\sf :\implies\:v=u+at:⟹v=u+at

Here,

v = 80 m/s

u = 20 m/s

a = 4 m/s²

Putting values,

\sf :\implies\:80=20+4t:⟹80=20+4t

\sf :\implies\:4t=80-20:⟹4t=80−20

\sf :\implies\:4t=60:⟹4t=60

\sf :\implies\:t=\dfrac{60}{4}:⟹t=

4

60

\sf :\implies\:t=15\:sec:⟹t=15sec

Hence, It will take 15 sec to become velocity 80 m/s.

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