Chemistry, asked by anu6433, 8 months ago

A gaseous hydrocarbon contains 82.76% of carbon. Given vapour density is 24, find malecular formula. [C=12, H=1]

if u know then only answer it

Answers

Answered by maniyachawla12

Answer: This may help you

Explanation:

Element %composition Mol. mass No. of C atoms Simplest Rounding

ratio off

C 82.76 12 6.89 1× 2 2

H 17.24 1 17.24 2.5× 2 5

Number of carbon atoms present

= 82.76/12

= 6.89

Number of hydrogen atoms present

= 17.24/1

= 17.24

simplest ratio

= 6.89/6.89 =1

simplest ratio

= 17.24/6.89

= 2.5

∴ Empirical formula is C2H5

Empirical formula mass= 2×12+5 = 29

∴ V.D. = 29

Mol. mass = 2 × V.D.

=58

n= Molecular mass/Empirical formula mass

= 58/29

∴ Molecular formula = C4H10

Answered by shivanityagi9410

Answer:

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A gaseous hydrocarbon contains 82.76% of carbon. Given vapour density is 24, find malecular formula. [C=12, H=1]if u know then only answer it​

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A gaseous hydrocarbon contains 82.76% of carbon. Given vapour density is 24, find malecular formula. [C=12, H=1]

if u know then only answer it