a circus tent is in the shape of a cylinder surmounted by a cone. the diameter of the cylindrical portion is 24 m and its height is 11 m.if the vertexof the cone is 16m above the ground,find the area of canvas used to make the tent
please I request I all to solve it fast
nazzy373:
anyone solve plzz
Answers
Answered by
6
Hiii friend,
Diameter = 24 m
radius = D/2 = 24/2 = 12 m
Height of the cylindrical part = 11 m
Total height of tent = 16 m
Height of conical part = Total height- Height of cylindrical part = 16-11 = 5 m
Slant Height = ✓(h)² + (r)² = ✓(5)² + (12)² = ✓25+144 = ✓169 = 13 m
Therefore,
Area of canvas used to make the tent = CSA of the cylinder + CSA of the cone
=> 2πrh + πrl
=> [ (2 × 22/7 × 12 × 11) + (22/7 × 12 × 13)]
=> ( 5808/7 + 3432/7)
=> ( 829.71 + 490.28)
=> 1319.99 m²
HOPE IT WILL HELP YOU...... :-)
Diameter = 24 m
radius = D/2 = 24/2 = 12 m
Height of the cylindrical part = 11 m
Total height of tent = 16 m
Height of conical part = Total height- Height of cylindrical part = 16-11 = 5 m
Slant Height = ✓(h)² + (r)² = ✓(5)² + (12)² = ✓25+144 = ✓169 = 13 m
Therefore,
Area of canvas used to make the tent = CSA of the cylinder + CSA of the cone
=> 2πrh + πrl
=> [ (2 × 22/7 × 12 × 11) + (22/7 × 12 × 13)]
=> ( 5808/7 + 3432/7)
=> ( 829.71 + 490.28)
=> 1319.99 m²
HOPE IT WILL HELP YOU...... :-)
Answered by
3
1319.99933 is the right answer.
hope it helps.
hope it helps.
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