Question

A city bus carrying 70 passengers, some with 3- rupee tickets and the remaining with
5-rupee tickets. If the total amount received by the conductor was Rs.300, find the
number of passengers of each type

Answer 1

Let those with 3 rupee tickets = x  

Let those with 5 rupee tickets = y  

We form and solve 2 simultaneous equations    

x + y = 70  ---- (i)  

3x + 5y = 300 ----- (ii)  

From (i)   y = 70 – x    

Substitute this in (ii)  

3x + 5(70 – x) = 300  

3x + 350 – 5x = 300  

3x – 5x = 300 – 350  

-2x = - 50   x = 25  

and    

y = 70 – 25 = 45    

Those with 3 rupee tickets = 25  

Those with 5 rupee tickets = 45    

Answer 2

Answer:

Step-by-step explanation:

Let those with 3 rupee tickets = x

Let those with 5 rupee tickets = y

We form and solve 2 simultaneous equations

x + y = 70 ---- (i)

3x + 5y = 300 ----- (ii)

From (i) y = 70 – x

Substitute this in (ii)

3x + 5(70 – x) = 300

3x + 350 – 5x = 300

3x – 5x = 300 – 350

-2x = - 50 x = 25

and

y = 70 – 25 = 45

Those with 3 rupee tickets = 25

Those with 5 rupee tickets = 45