Question

a closed biscuit box made of tin is cylinder in shape of height 80 cm and base radius of 63cm .How many sqaure metres of tin has been used to make the box? What will be its cost if m^2 of tin cost Rs 5 ??

Answer 1

here is the solved solution

Answer 2

5.6628 sq.m. of tin has been used to make the box and its cost is Rs.28.314

Step-by-step explanation:

Height of cylindrical box = 80 cm

Radius of cylindrical box = 63 cm

Total surface area of cylindrical box = $2 \pi r h + 2\pi r^2$

Total surface area of cylindrical box =$2 \times \frac{22}{7} \times 63 \times 80 + 2 \times \frac{22}{7} \times 63^2=56628 cm^2$

$10000 cm^2 = 1 m^2$

$56628 cm^2 = \frac{56628}{10000}=5.6628 m^2$

Cost of 1 sq.m. of tin = Rs.5

Cost of 5.6628 sq.m. of tin = $5.6628 \times 5 = Rs.28.314$

Hence 5.6628 sq.m. of tin has been used to make the box and its cost is Rs.28.314

#Learn more:

An open cylindrical can of radius 7cm and height 14cm need to be made from a tin sheet, what is the total area of sheet required?

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