Question

A closed coil of 40 turns and area 200 cm? is rotated in a magnetic field of flux density 2 Wbm?. It rotates from a position where its plane makes an angle of 30° with the field to a position perpendicular to the field in a time 0.2s. Find the magnitude of the emf induced in the coil due to its rotation.

Answer 1

Answer:

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Answer 2

Explanation:

Given A closed coil of 40 turns and area 200 cm^2 is rotated in a magnetic field of flux density 2 Wbm^2. It rotates from a position where its plane makes an angle of 30° with the field to a position perpendicular to the field in a time 0.2 s. Find the magnitude of the emf induced in the coil due to its rotation.

• Given N = 40 turns
• Area A = 200 cm^2
• Magnetic field B = 2 wb m^2
• Angle = 30 degree, so theta = 90 – 30 = 60 degree
• Now φ initial = BA cos theta
•                        = 2 x 200 x 10^-4 cos 60  
•                        = 2 x 10^-2 Wb
• Also final flux φ final = BA cos theta
•                                     = 2 x 200 x 10^-4 cos 0
•                                     = 4 x 10^-2 Wb
•                  Now dt = 0.2 s
• So magnitude of induced emf will be ε = N dφ / dt
•                                                                  = 40 x (4 x 10^-2 – 2 x 01^-2) / 0.2
•                                                                  = 4 V

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