Question

a closed container has 7 GM's nitrogen 0.1 mole of carbon dioxide 2.4 gms of lowest molecular weight hydrocarbon find the average molecular mass of mixture​

Answer 1

Explanation:

Moles of N2=28280=10moles 

Assume, moles of CO2=x.  

So, average molecular mass of mixture =10+x10×28+x×44 =36 (given)

So, x=10 moles

Therefore, weight of CO2=10×44=440 g

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Answer 2

The mass of Nitrogen (N) present in a closed container$\\ = 7 gm$

The mole of Carbon dioxide (CO₂) present in a closed container $\\ = 0.1$

Molecular Mass of Carbon dioxide (CO₂)$\\ =44 gm ( 12 + (16\times2) )$

The mass of Carbon dioxide (CO₂) present in a closed container$\\ = 0.1\times4=4.4 gm$

The mass of lowest molecular weight hydrocarbon present in a closed container $\\ =2.4 gm$

So, the average molecular mass of the mixture $\\ = 7 gm + 4.4 gm + 2.4 gm = 13.8 gm$

Hence, the average molecular mass of the mixture $\\ = 13.8 gm.$