Question

a coil of area 5cm^2 has 10 turns It is situated in the magnetic field such that coil makes an angle 60 degree with the direction of field what will be magnetic flux link with the coil​

Answer 1

Answer:

Area of the coil A=5cm

2

=5×10

−4

m

2

Number of turns N=20

Magnetic field B=10

3

Gauss =10

−1

T

Angle between magnetic field and normal to the plane of coil θ=30

o

Thus flux through the coil ϕ=NBAcosθ

∴ ϕ=20×10

−1

×5×10

−4

×0.865=8.65×10

−4

Wb