A coin is tossed 100 times the probability of getting head on odd times is
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No. Of times tossed N=100 , Parameters P=1/2
Required probability = P(x=1)+P(x=3)+.....P(x=99)
=(1/2)^100[100C1+100C3+.....+100C99]
1/2^100[299]
1/2
Required probability = P(x=1)+P(x=3)+.....P(x=99)
=(1/2)^100[100C1+100C3+.....+100C99]
1/2^100[299]
1/2
Anonymous:
It is 1/2
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