A coin is tossed three times what is the probability of getting head and tail alternatively
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A = { getting head and tail alternatively }
A = { HTH,THT }
n(A) = 2 n(S) = 8
p(A) = n(A)/n(S) = 2/8 (or) 1/4
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A = { HTH,THT }
n(A) = 2 n(S) = 8
p(A) = n(A)/n(S) = 2/8 (or) 1/4
HOPE IT HELPS
PLZ MARK ME AS BRAINLIEST
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