Question

A coin is tossed thrice .what is the probability of getting two heads and one tail.

Answer 1

Total outcomes be HHH, HHT, HTH, HTT, TTT, TTH, THT, THH.
$p(getting \: two \: head \: and \: one \: tail) = \frac{no \: of \: favourable \: outcome}{total \: no \: of \: outcome} \\ = \frac{3}{8}$

Answer 2

Answer:

The probability of getting two heads and one tail is $\frac{3}{8}$.

Step-by-step explanation:

Step 1

Probability means possibilities. It is the occurrence of random events.

The probability of all the events in a sample space adds up to 1.

Step 2

When a coin is tossed the total outcomes are

HHH,HHT,HTH,HTT,TTT,TTH,THT,THH.

Hence, the probability of getting two heads and one tail will be $\frac{3}{8}$.