ABCD is a rectangle If the sides of triangle are in A. P the perimeter of the triangle is 30cm the different between the longer and shorter side is 4 cm then find all sides of the triangle.
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Answered by
5
HEYA FRIEND ✋✋✋
PERIMETER = 30CM
THE THREE SIDES ARE A , A + D , A + 2D
A + 2D - A = 4
D = 2
PERIMETER = A + A + D + A + 2D
3A + 6 = 30
A = 8 CM
A + D = 10 CM
A + 2D = 12 CM
HOPE IT HELPS
PERIMETER = 30CM
THE THREE SIDES ARE A , A + D , A + 2D
A + 2D - A = 4
D = 2
PERIMETER = A + A + D + A + 2D
3A + 6 = 30
A = 8 CM
A + D = 10 CM
A + 2D = 12 CM
HOPE IT HELPS
mysticd:
it is wrong.
plz , edit
ya thank you
Answered by
1
Hi ,
Let ( a - d ) , a , ( a + d ) are sides of the
Triangle ABC ,
perimeter = 30 cm
a - d + a + a+ d = 30 cm
3a = 30
a = 30 / 3
a = 10
according to the problem given ,
a + d - ( a - d ) = 4 cm
2d = 4
d = 4/2
d = 2
THEREFORE,
Three sides are ,
a - d = 10 - 2 = 8
a = 10
a + d = 10 + 2 = 12 cm
I hope this helps you.
:)
Let ( a - d ) , a , ( a + d ) are sides of the
Triangle ABC ,
perimeter = 30 cm
a - d + a + a+ d = 30 cm
3a = 30
a = 30 / 3
a = 10
according to the problem given ,
a + d - ( a - d ) = 4 cm
2d = 4
d = 4/2
d = 2
THEREFORE,
Three sides are ,
a - d = 10 - 2 = 8
a = 10
a + d = 10 + 2 = 12 cm
I hope this helps you.
:)
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