Question

A coin is tossed two times Find the probability of getting (i) no tail (ii) at most one tail (iii) one head​

Answer 1

The results will be HH, TT, HT, TH

i)1/4

ii) 3/4

iii)2/4=1/2

hope this helps you.

Answer 2

Step-by-step explanation:

probability ( No Tail ) = The possible outcomes are:

H H,H T, T H, T T

Only one of these outcomes is ‘favorable’ in that no Tail occurs, and that is the first combination of two heads H H

The chance is therefore one in four = 1/4 = 0.25

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probability ( One Tail ) = Assuming that the coin is “fair”, i.e. that the probability of tails = probability of heads = 0.5, then:

Possible outcomes: HH, HT, TH, TT

At least one tail: HT, TH, TT

From the definition of probability, the number you want is 3/4=0.75=75%

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probability ( One Head ) = Assuming that the coin is “fair”, i.e. that the probability of head = probability of heads = 0.5, then:

Possible outcomes: HH, HT, TH, TT

At least one Head: HT, TH, HH

From the definition of probability, the number you want is 3/4=0.75=75%

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Thank You