A coin placed on a rotating turntable just slips if it is placed at a distance of 16 cm from the centre. If the angular velocity of the turntable is doubled, it will just slip at a distance of
Answers
Answered by
0
hey mate here is your answer...
⭐⭐⭐⭐⭐⭐
(w= angular velocity)
F= m w^2 r
F slip= m w^2 40. --> eqn(1)
F slip= m (2w)^2 R2
F slip=4m w^2 R2 --> eqn(2)
solving 1 and 2
m w^2 40 = 4 m w^2 R2
so R2 = 10 cm.
ⓗⓞⓟⓔ ⓘⓣ ⓗⓔⓛⓟⓢ ⓨⓞⓤ ⓓⓔⓐⓡ..
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
thanks for question....
⭐⭐⭐⭐⭐⭐
(w= angular velocity)
F= m w^2 r
F slip= m w^2 40. --> eqn(1)
F slip= m (2w)^2 R2
F slip=4m w^2 R2 --> eqn(2)
solving 1 and 2
m w^2 40 = 4 m w^2 R2
so R2 = 10 cm.
ⓗⓞⓟⓔ ⓘⓣ ⓗⓔⓛⓟⓢ ⓨⓞⓤ ⓓⓔⓐⓡ..
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
thanks for question....
Similar questions