Question

A coin with head and tail is tossed. find the probability that
1) a head turns up,
2) a tail turns up, and
3) both head and tail trun up. ​

Answer 1

Answer:

Step-by-step explanation:he probability of getting heads on the toss of a coin is 0.5. ... There are four possible mutually exclusive outcomes on the toss of two coins as shown, each with a probability of 0.25. The sum of the probability of two of these outcomes (heads, tails or tails, heads) is 0.25 + 0.25 or 0.5.

Answer 2

Heya!!

Here's your answer!!

Since a coin can result in 2 outcomes of head or tail, n(s) = 2

(i) Let A be the event that H turns up = n(A) = 1

Thus, P(A) = n(A)/n(s) = 1/2

(ii) If B is an event that a tail turns up then

P(B) = n(B)/n(s) = 1/2

(iii) For a single coin, H or T both cannot turn up simultaneously.

Thus, P(H and T both) = 0

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