Question

A compound forms hcp structure.Total num od voids is 0.5 mol of it? How many of these are tetrahedral voids

Answer 1

Explanation:

Number of atoms in close packaging = 0.5 mol

1 has 6.022 ×1023 particles

So that

Number of close−packed particles

= 0.5 × 6.022 × 1023 = 3.011 × 1023

Number of tetrahedral voids = 2 × number of atoms in close packaging

Plug the values we get

Number of tetrahedral voids = 2 × 3.011 × 1023

= 6.022 × 1023

Number of octahedral voids = number of atoms in close packaging

So that

Number of octahedral voids = 3.011 × 1023

Total number of voids = Tetrahedral void + octahedral void

= 6.022 × 1023 + 3.011 × 1023

= 9.03 × 1023