A compound was found to have 78.2% Boron and 21.8% hydrogen.Its molecular mass was found to be a 27.6 g/mol.What is the molecular formula of the compound?
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Answer:
Element
Mass (g)
78.2 21.8
Moles
78.2/10.8 21.8/1
(moles mass/molar mass of atoms of the
element)
Ratio 7.24
Divide by 7.24/7.24 21.8/7.24
(this makes the number of atoms of the
smallest one = 1)
Approx
Approx 3
Empirical (simplest) formula = BH3
smallest 3.01
This has a formula mass of 10.8 +1 x 3 = 13.8 So the molecular formula is 27.6/13.8 = 2.0 times bigger than the empirical formula So molecular formula is B2H6
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