Question

Two blocks of masses 1 kg and 2 kg are connected with massless spring as shown. If the acceleration of 1 kg block is 1 m/s2 towards right then the acceleration of 2 kg block is

(1)1 m/s2
(2) 3 m/s2
(3) 2m/s2​

Answer 1

Answer:

2m/s^2

Explanation:

m1 = 1kg. and m2=2kg

F=5N and a1= 1m/s^2

a2 ?

For mass m1:-

F1= m1× a1

F1 = 1×1= 1N

For mass m2:-

5N - F2= m2 × a2

5-F2= 2 ×a2

5-1 = 2×a2

a2= 4m/s^2

Answer 2

✪ᴀɴsᴡᴇʀ✪

• (3) Acceleration of 2Kg mass = 2m/s²

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

☆ɢɪᴠᴇɴ☆

• Two masses of 1Kg and 2Kg connected by a spring
• When 5N force is applied on 2Kg mass, the 1Kg mass experience acceleration of 1m/s²

☆ᴛᴏ ғɪɴᴅ☆

• Acceleration of 2 Kg mass

☆ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ☆

Let F be the tensile force developed in the spring due to extension. And let a be the acceleration of 2Kg mass.

✯sᴘʀɪɴɢ ғᴏʀᴄᴇ

By applying Newton's Second Law on the 1 Kg mass, we get

F = 1Kg x 1 m/s²

⇒ F = 1 N

✯ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ

By applying Newton's Second Law on the 2 Kg mass, we get

5 - F = 2 x a

⇒ 5 - 1 = 2a

⇒ 4 = 2a

⇒ a = 2 m/s²

Thus, the 2Kg mass experience an acceleration of 2 m/s².