A concrete wall of thickness one metre of a dam can withstand a side pressur e of 1 0 5 2 N m - . Find the thickness of sidewal l at the bottom of the water dam at a depth of 100 m. [ g = - 1 0 2 m s and density of w ater = 1 0 3 kg/ m 3
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Pressure at 100m100m=105Pa+100m∗1000kg/m3∗10m/s−2=105Pa+100m∗1000kg/m3∗10m/s−2
=1100000Pa=1100000Pa
=11∗105Pa=11∗105Pa
Pressure/Thickness=kPressure/Thickness=k
k=105k=105
So11∗105/x=105So11∗105/x=105
Thickness(x)=11m
=1100000Pa=1100000Pa
=11∗105Pa=11∗105Pa
Pressure/Thickness=kPressure/Thickness=k
k=105k=105
So11∗105/x=105So11∗105/x=105
Thickness(x)=11m
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